Optimal. Leaf size=152 \[ \frac{5 b^3 (A b-8 a B) \tanh ^{-1}\left (\frac{\sqrt{a+b x^2}}{\sqrt{a}}\right )}{128 a^{3/2}}+\frac{5 b^2 \sqrt{a+b x^2} (A b-8 a B)}{128 a x^2}+\frac{\left (a+b x^2\right )^{5/2} (A b-8 a B)}{48 a x^6}+\frac{5 b \left (a+b x^2\right )^{3/2} (A b-8 a B)}{192 a x^4}-\frac{A \left (a+b x^2\right )^{7/2}}{8 a x^8} \]
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Rubi [A] time = 0.11766, antiderivative size = 152, normalized size of antiderivative = 1., number of steps used = 7, number of rules used = 5, integrand size = 22, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.227, Rules used = {446, 78, 47, 63, 208} \[ \frac{5 b^3 (A b-8 a B) \tanh ^{-1}\left (\frac{\sqrt{a+b x^2}}{\sqrt{a}}\right )}{128 a^{3/2}}+\frac{5 b^2 \sqrt{a+b x^2} (A b-8 a B)}{128 a x^2}+\frac{\left (a+b x^2\right )^{5/2} (A b-8 a B)}{48 a x^6}+\frac{5 b \left (a+b x^2\right )^{3/2} (A b-8 a B)}{192 a x^4}-\frac{A \left (a+b x^2\right )^{7/2}}{8 a x^8} \]
Antiderivative was successfully verified.
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Rule 446
Rule 78
Rule 47
Rule 63
Rule 208
Rubi steps
\begin{align*} \int \frac{\left (a+b x^2\right )^{5/2} \left (A+B x^2\right )}{x^9} \, dx &=\frac{1}{2} \operatorname{Subst}\left (\int \frac{(a+b x)^{5/2} (A+B x)}{x^5} \, dx,x,x^2\right )\\ &=-\frac{A \left (a+b x^2\right )^{7/2}}{8 a x^8}+\frac{\left (-\frac{A b}{2}+4 a B\right ) \operatorname{Subst}\left (\int \frac{(a+b x)^{5/2}}{x^4} \, dx,x,x^2\right )}{8 a}\\ &=\frac{(A b-8 a B) \left (a+b x^2\right )^{5/2}}{48 a x^6}-\frac{A \left (a+b x^2\right )^{7/2}}{8 a x^8}-\frac{(5 b (A b-8 a B)) \operatorname{Subst}\left (\int \frac{(a+b x)^{3/2}}{x^3} \, dx,x,x^2\right )}{96 a}\\ &=\frac{5 b (A b-8 a B) \left (a+b x^2\right )^{3/2}}{192 a x^4}+\frac{(A b-8 a B) \left (a+b x^2\right )^{5/2}}{48 a x^6}-\frac{A \left (a+b x^2\right )^{7/2}}{8 a x^8}-\frac{\left (5 b^2 (A b-8 a B)\right ) \operatorname{Subst}\left (\int \frac{\sqrt{a+b x}}{x^2} \, dx,x,x^2\right )}{128 a}\\ &=\frac{5 b^2 (A b-8 a B) \sqrt{a+b x^2}}{128 a x^2}+\frac{5 b (A b-8 a B) \left (a+b x^2\right )^{3/2}}{192 a x^4}+\frac{(A b-8 a B) \left (a+b x^2\right )^{5/2}}{48 a x^6}-\frac{A \left (a+b x^2\right )^{7/2}}{8 a x^8}-\frac{\left (5 b^3 (A b-8 a B)\right ) \operatorname{Subst}\left (\int \frac{1}{x \sqrt{a+b x}} \, dx,x,x^2\right )}{256 a}\\ &=\frac{5 b^2 (A b-8 a B) \sqrt{a+b x^2}}{128 a x^2}+\frac{5 b (A b-8 a B) \left (a+b x^2\right )^{3/2}}{192 a x^4}+\frac{(A b-8 a B) \left (a+b x^2\right )^{5/2}}{48 a x^6}-\frac{A \left (a+b x^2\right )^{7/2}}{8 a x^8}-\frac{\left (5 b^2 (A b-8 a B)\right ) \operatorname{Subst}\left (\int \frac{1}{-\frac{a}{b}+\frac{x^2}{b}} \, dx,x,\sqrt{a+b x^2}\right )}{128 a}\\ &=\frac{5 b^2 (A b-8 a B) \sqrt{a+b x^2}}{128 a x^2}+\frac{5 b (A b-8 a B) \left (a+b x^2\right )^{3/2}}{192 a x^4}+\frac{(A b-8 a B) \left (a+b x^2\right )^{5/2}}{48 a x^6}-\frac{A \left (a+b x^2\right )^{7/2}}{8 a x^8}+\frac{5 b^3 (A b-8 a B) \tanh ^{-1}\left (\frac{\sqrt{a+b x^2}}{\sqrt{a}}\right )}{128 a^{3/2}}\\ \end{align*}
Mathematica [A] time = 0.092213, size = 140, normalized size = 0.92 \[ \frac{-\left (a+b x^2\right ) \left (8 a^2 b x^2 \left (17 A+26 B x^2\right )+16 a^3 \left (3 A+4 B x^2\right )+2 a b^2 x^4 \left (59 A+132 B x^2\right )+15 A b^3 x^6\right )-15 b^3 x^8 \sqrt{\frac{b x^2}{a}+1} (8 a B-A b) \tanh ^{-1}\left (\sqrt{\frac{b x^2}{a}+1}\right )}{384 a x^8 \sqrt{a+b x^2}} \]
Antiderivative was successfully verified.
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Maple [B] time = 0.02, size = 311, normalized size = 2.1 \begin{align*} -{\frac{A}{8\,a{x}^{8}} \left ( b{x}^{2}+a \right ) ^{{\frac{7}{2}}}}+{\frac{Ab}{48\,{a}^{2}{x}^{6}} \left ( b{x}^{2}+a \right ) ^{{\frac{7}{2}}}}+{\frac{A{b}^{2}}{192\,{a}^{3}{x}^{4}} \left ( b{x}^{2}+a \right ) ^{{\frac{7}{2}}}}+{\frac{A{b}^{3}}{128\,{a}^{4}{x}^{2}} \left ( b{x}^{2}+a \right ) ^{{\frac{7}{2}}}}-{\frac{A{b}^{4}}{128\,{a}^{4}} \left ( b{x}^{2}+a \right ) ^{{\frac{5}{2}}}}-{\frac{5\,A{b}^{4}}{384\,{a}^{3}} \left ( b{x}^{2}+a \right ) ^{{\frac{3}{2}}}}+{\frac{5\,A{b}^{4}}{128}\ln \left ({\frac{1}{x} \left ( 2\,a+2\,\sqrt{a}\sqrt{b{x}^{2}+a} \right ) } \right ){a}^{-{\frac{3}{2}}}}-{\frac{5\,A{b}^{4}}{128\,{a}^{2}}\sqrt{b{x}^{2}+a}}-{\frac{B}{6\,a{x}^{6}} \left ( b{x}^{2}+a \right ) ^{{\frac{7}{2}}}}-{\frac{Bb}{24\,{a}^{2}{x}^{4}} \left ( b{x}^{2}+a \right ) ^{{\frac{7}{2}}}}-{\frac{B{b}^{2}}{16\,{a}^{3}{x}^{2}} \left ( b{x}^{2}+a \right ) ^{{\frac{7}{2}}}}+{\frac{B{b}^{3}}{16\,{a}^{3}} \left ( b{x}^{2}+a \right ) ^{{\frac{5}{2}}}}+{\frac{5\,B{b}^{3}}{48\,{a}^{2}} \left ( b{x}^{2}+a \right ) ^{{\frac{3}{2}}}}-{\frac{5\,B{b}^{3}}{16}\ln \left ({\frac{1}{x} \left ( 2\,a+2\,\sqrt{a}\sqrt{b{x}^{2}+a} \right ) } \right ){\frac{1}{\sqrt{a}}}}+{\frac{5\,B{b}^{3}}{16\,a}\sqrt{b{x}^{2}+a}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F(-2)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Exception raised: ValueError} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 1.82248, size = 628, normalized size = 4.13 \begin{align*} \left [-\frac{15 \,{\left (8 \, B a b^{3} - A b^{4}\right )} \sqrt{a} x^{8} \log \left (-\frac{b x^{2} + 2 \, \sqrt{b x^{2} + a} \sqrt{a} + 2 \, a}{x^{2}}\right ) + 2 \,{\left (3 \,{\left (88 \, B a^{2} b^{2} + 5 \, A a b^{3}\right )} x^{6} + 48 \, A a^{4} + 2 \,{\left (104 \, B a^{3} b + 59 \, A a^{2} b^{2}\right )} x^{4} + 8 \,{\left (8 \, B a^{4} + 17 \, A a^{3} b\right )} x^{2}\right )} \sqrt{b x^{2} + a}}{768 \, a^{2} x^{8}}, \frac{15 \,{\left (8 \, B a b^{3} - A b^{4}\right )} \sqrt{-a} x^{8} \arctan \left (\frac{\sqrt{-a}}{\sqrt{b x^{2} + a}}\right ) -{\left (3 \,{\left (88 \, B a^{2} b^{2} + 5 \, A a b^{3}\right )} x^{6} + 48 \, A a^{4} + 2 \,{\left (104 \, B a^{3} b + 59 \, A a^{2} b^{2}\right )} x^{4} + 8 \,{\left (8 \, B a^{4} + 17 \, A a^{3} b\right )} x^{2}\right )} \sqrt{b x^{2} + a}}{384 \, a^{2} x^{8}}\right ] \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [B] time = 159.292, size = 316, normalized size = 2.08 \begin{align*} - \frac{A a^{3}}{8 \sqrt{b} x^{9} \sqrt{\frac{a}{b x^{2}} + 1}} - \frac{23 A a^{2} \sqrt{b}}{48 x^{7} \sqrt{\frac{a}{b x^{2}} + 1}} - \frac{127 A a b^{\frac{3}{2}}}{192 x^{5} \sqrt{\frac{a}{b x^{2}} + 1}} - \frac{133 A b^{\frac{5}{2}}}{384 x^{3} \sqrt{\frac{a}{b x^{2}} + 1}} - \frac{5 A b^{\frac{7}{2}}}{128 a x \sqrt{\frac{a}{b x^{2}} + 1}} + \frac{5 A b^{4} \operatorname{asinh}{\left (\frac{\sqrt{a}}{\sqrt{b} x} \right )}}{128 a^{\frac{3}{2}}} - \frac{B a^{3}}{6 \sqrt{b} x^{7} \sqrt{\frac{a}{b x^{2}} + 1}} - \frac{17 B a^{2} \sqrt{b}}{24 x^{5} \sqrt{\frac{a}{b x^{2}} + 1}} - \frac{35 B a b^{\frac{3}{2}}}{48 x^{3} \sqrt{\frac{a}{b x^{2}} + 1}} - \frac{B b^{\frac{5}{2}} \sqrt{\frac{a}{b x^{2}} + 1}}{2 x} - \frac{3 B b^{\frac{5}{2}}}{16 x \sqrt{\frac{a}{b x^{2}} + 1}} - \frac{5 B b^{3} \operatorname{asinh}{\left (\frac{\sqrt{a}}{\sqrt{b} x} \right )}}{16 \sqrt{a}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A] time = 1.16437, size = 263, normalized size = 1.73 \begin{align*} \frac{\frac{15 \,{\left (8 \, B a b^{4} - A b^{5}\right )} \arctan \left (\frac{\sqrt{b x^{2} + a}}{\sqrt{-a}}\right )}{\sqrt{-a} a} - \frac{264 \,{\left (b x^{2} + a\right )}^{\frac{7}{2}} B a b^{4} - 584 \,{\left (b x^{2} + a\right )}^{\frac{5}{2}} B a^{2} b^{4} + 440 \,{\left (b x^{2} + a\right )}^{\frac{3}{2}} B a^{3} b^{4} - 120 \, \sqrt{b x^{2} + a} B a^{4} b^{4} + 15 \,{\left (b x^{2} + a\right )}^{\frac{7}{2}} A b^{5} + 73 \,{\left (b x^{2} + a\right )}^{\frac{5}{2}} A a b^{5} - 55 \,{\left (b x^{2} + a\right )}^{\frac{3}{2}} A a^{2} b^{5} + 15 \, \sqrt{b x^{2} + a} A a^{3} b^{5}}{a b^{4} x^{8}}}{384 \, b} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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